product finite model property. Here we answer a question of Gabbay and. Shehtman by showing that S5 × S5 × S5 also lacks the 'real' finite model property (fmp).
This implies that the product logic S5 × S5 × S5 does not have the product finite model property. Here we answer a question of Gabbay and Shehtman by showing ...
This implies that the product logic S5 × S5 × S5 does not have the product finite model property. Here we answer a question of Gabbay and Shehtman by showing ...
S5 x S5 x S5 Lacks the Finite Model Property.Agnes Kurucz - 1998 - In Marcus Kracht, Maarten de Rijke, Heinrich Wansing & Michael Zakharyaschev (eds.), Advances ...
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What is the finite model property of modal logic?
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The modal technique of filtration provides the decidability result plus the finite model property. ... [8] KURUCZ, A., 'S5 x S5 x S5 lacks the finite model ...
To show that a logic L has the finite model property via filtrations it is essential that the filtration of an L-model is itself a L-model. Often this re-.
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ON MODAL LOGICS BETWEEN K × K × K AND S5 × S5 × S5. 3. For any natural ... S5xS5xS5 lacks the finite model property. Accepted at AiML-ICTL'2000. Avail ...
Abstract. Two-dimensional products of modal logics having at least one 'non-transitive' component, such as K x K, K x K4, and K x S5,.
Quantification over public announcements shifts the perspective from reasoning strictly about the results of a particular announcement to reasoning about ...
Products of Modal Logics with Diagonal Constant Lacking the Finite Model Property ... S5, are often known to be decidable and have the finite model property. Here ...