The vertices of TK corresponding to the vertices of K are its branch vertices. Kelmans [6] and, independently, Seymour [11] conjectured that every 5-connected ...
We characterize graphs G that contain no diamond on a prescribed set Z of four vertices, under the assumption that for every v ∈ Z there are three paths of G ...
Sep 19, 2016 · Title:The Kelmans-Seymour conjecture III: 3-vertices in K_4^-. Authors:Dawei He, Yan Wang, Xingxing Yu. View a PDF of the paper titled The ...
Missing: K4-. | Show results with:K4-.
Dec 9, 2019 · In this paper, we prove the following, which can be used to take care of (b). Theorem 1.1. Let G be a 5-connected nonplanar graph and x1,x2,y1, ...
The Kelmans-Seymour conjecture III: 3-vertices in K4- · Dawei He, Yan Wang, Xingxing Yu · Published in J. Comb. Theory B 24 February 2016 · Mathematics · J. Comb.
Download Citation | The Kelmans-Seymour conjecture III: 3-vertices in $K_4^- | Let $G$ be a 5-connected nonplanar graph and let $x_1,x_2,y_1,y_2\in V(G)$ be ...
The Kelmans-Seymour conjecture III: 3-vertices in $K_4^-$ ... Abstract. Let $G$ be a 5-connected nonplanar graph and let $x_1,x_2,y_1,y_2\in V(G)$ be distinct, ...
Missing: K4-. | Show results with:K4-.
In graph theory, the Kelmans–Seymour conjecture states that every 5-vertex-connected graph that is not planar contains a subdivision of the 5-vertex complete ...
Mar 9, 2016 · We show that G contains a K_4^- in which x1 is of degree 2, or G-x1 contains K_4^-, or G contains a TK_5 in which x1 is not a branch vertex, or ...
Missing: K4-. | Show results with:K4-.
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How many paths of length 3 are there in between any 2 different vertices of k4?
In order to establish the Kelmans-Seymour conjecture for all graphs, we need to consider 5-separations and 6-separations with less restrictive structures. The ...