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A005267
a(n) = -1 + a(0)*a(1)*...*a(n-1) with a(0) = 3.
(Formerly M2248)
8
3, 2, 5, 29, 869, 756029, 571580604869, 326704387862983487112029, 106735757048926752040856495274871386126283608869, 11392521832807516835658052968328096177131218666695418950023483907701862019030266123104859068029
OFFSET
0,1
COMMENTS
The next term is too large to include.
An infinite coprime sequence defined by recursion. - Michael Somos, Mar 14 2004
Let u(k), v(k) be defined by u(1)=1, v(1)=3, u(k+1)=v(k)-u(k), v(k+1)=u(k)v(k); then a(n)=v(2n). - Benoit Cloitre, Apr 02 2002
For positive n, a(n) has digital root 2 or 5 depending on whether n is odd or even. (T. Koshy) - Lekraj Beedassy, Apr 11 2005
REFERENCES
R. K. Guy and R. Nowakowski, "Discovering primes with Euclid," Delta (Waukesha), Vol. 5, pp. 49-63, 1975.
T. Koshy, "Intriguing Properties Of Three Related Number Sequences", in Journal of Recreational Mathematics, Vol. 32(3) pp. 210-213, 2003-2004 Baywood NY.
N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
LINKS
R. K. Guy and R. Nowakowski, Discovering primes with Euclid, Research Paper No. 260 (Nov 1974), The University of Calgary Department of Mathematics, Statistics and Computing Science.
FORMULA
a(n) = -1 + a(0)a(1)...a(n-1).
a(n) = -1 + Product_{i<n} a(i). - Henry Bottomley, Jul 31 2000
a(n+1) = a(n)^2 + a(n) - 1 if n>1. a(0)=3, a(1)=2.
An induction shows that a(n+1) = A117805(n) - 1. - R. J. Mathar, Apr 22 2007; M. F. Hasler, May 04 2007
For n>0, a(n) = a(0)^2 + a(1)^2 + ... + a(n-1)^2 - n - 6. - Max Alekseyev, Jun 19 2008
PROG
(PARI) a(n)=if(n<2, 3*(n>=0)-(n>0), a(n-1)^2+a(n-1)-1)
(Python)
def a(n):
if n == 0: return 2
t = a(n-1)
l = t+1
u = t
return l * u - 1
print([a(n) for n in range(0, 8)]) # Dar�o Clavijo, Aug 24 2024
CROSSREFS
KEYWORD
easy,nonn
STATUS
approved