OFFSET
0,4
COMMENTS
For n with 2^k - 1 <= n < 2^k + k-1: a(n) = k;
for n with 2^k + k-1 <= n < 2^(k+1) - 1: a(n) = 0.
FORMULA
a(n) = f(n,0) with f(n,k) = if n<2^k then (if n<k then k else 0) else f(n-2^k,k+1).
CROSSREFS
KEYWORD
nonn,tabf
AUTHOR
Reinhard Zumkeller, May 24 2009
STATUS
approved